Question

The sum of magnitudes of two forces is 16N. If the resultant force is 8N and its direction is perpendicular to minimum force then the forces are A. ON and 1ON B. &N and 8N C.4N and 12N D.2N and 14N
explain with proof​

Answer 1

Answer:

A+B=16...(1)

tanα=

A+Bcosθ

Bsinθ

=tan90

Thus, A+Bcosθ=0⇒cosθ=−

B

A

...(2)

We also have: 8=

A

2

+B

2

+2ABcosθ

...(3)

Solving these we get, A=6N and B=10N