The sum of magtides of two forces acting at a point is 16 N.If their resultant is normal to the smaller force and has a magnitude of 8 N. the forces are:
et the forces be p and q .
Its given that the sum of the two forces i.e.
p + q = 16 N
the resultant of the two forces is 8 N and is perpendicular to the minimum force.
the minimum force can be in a situation where the two are opposite to each other and if the resultant is perpendicular to the direction of minimum force
the force p, q may be making a triangle having R rt. angle at the
direction of p-q.
therefore it must satisfy the relation p^2 + R^2 = q^2
therefore R^2 = q^2 - p^2
as p = 16 - q one can write p^2 = (16-q)^2
or R^2 = q^2 - (16-q)^2 = (q +16 -q) (q -16 +q ) =( 2.q -16 ) .16
R=8 N ; R^2 = 64
64/16 = 2.q -16 or
q = 10N
and p = 16- q = 16- 10 = 6 N