asked by pratham982, 11 days ago

# The sum of magtides of two forces acting at a point is 16 N.If their resultant is normal to the smaller force and has a magnitude of 8 N. the forces are:​

0

et the forces be p and q .

Its given that the sum of the two forces i.e.

p + q = 16 N

the resultant of the two forces is 8 N and is perpendicular to the minimum force.

the minimum force can be in a situation where the two are opposite to each other and if the resultant is perpendicular to the direction of minimum force

the force p, q may be making a triangle having R rt. angle at the

direction of p-q.

therefore it must satisfy the relation p^2 + R^2 = q^2

therefore R^2 = q^2 - p^2

as p = 16 - q one can write p^2 = (16-q)^2

or R^2 = q^2 - (16-q)^2 = (q +16 -q) (q -16 +q ) =( 2.q -16 ) .16

R=8 N ; R^2 = 64

64/16 = 2.q -16 or

q = 10N

and p = 16- q = 16- 10 = 6 N

Explanation:

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