Question

the sum of mole fractions of a b and c in an aqueous solution containing 0.2 moles of each a b and c is (A)0.6 (B)0.2 (C)1.0 (D)0.1
(with explaination)

Answer 1

MOLE FRACTION = NO. OF MOLES OF SOLUTE / NO.OF MOLES OF SOLUTE + NO. OF MOLES OF SOLVENT
1. MOLE FRACTION OF A = 0.6 / 0.6+5
=0.6/5.6
3/28
MOLE FRACTION OF B AND C = 3/28 THERE THE SUM OF MOLE FRACTION OF A B AND C = 3*3/28
=9/28
=0.321 
OOPS I THINK O.321 IS NEAREST TO 0.1 SO ANSWER MAY BE 0.1