Question

the sum of multiplicative inverse of 7/3 and additive inverse of -5/9 is​

Answer 1

Step-by-step explanation:

21 and -45. is the answer

Answer 2

To Find :

We have to find the sum of the multiplicative inverse of $\frac{7}{3}$ and the additive inverse of $\frac{-5}{9}$

Solution:

The multiplicative inverse of a number is defined as the value which when multiplied by the original number results in 1.

⇒ The multiplicative inverse of  $\frac{7}{3}$  is  $\frac{3}{7}$.

The additive inverse of a number is the number when added to a given number that gives 0.

⇒ The additive inverse of  $\frac{-5}{9}$ is $\frac{5}{9}$.

∴ The sum of the multiplicative inverse of $\frac{7}{3}$ and the additive inverse of $\frac{-5}{9}$ is equal to,

                   $\[\begin{array}{c} = \frac{3}{7} + \frac{5}{9}\\\\ = \frac{{62}}{{63}}\end{array}\]$

Hence, the sum is equal to $\frac{62}{63}$