Math, asked by praveenkumar780395, 3 months ago

the sum of n.2n,3n terms of an ap are s1,s2,s3 respectively prove that s3=3(s2-s1)

Answers

Answered by hemadd
1

Step-by-step explanation:

sum of n=s1=1

sum of 2n=s2=2

sum of 3n=s3=3

s3=3(s2-s1)

3=3(2-1)

3=3*1

3=3

LHS =RHS

Hence proved

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