the sum of n.2n,3n terms of an ap are s1,s2,s3 respectively prove that s3=3(s2-s1)
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Step-by-step explanation:
sum of n=s1=1
sum of 2n=s2=2
sum of 3n=s3=3
s3=3(s2-s1)
3=3(2-1)
3=3*1
3=3
LHS =RHS
Hence proved
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