The sum of n number of AP is n^2+3. Find its 20th term
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we know ,
Tn = Sn - S(n-1)
Tn =n^2 +3 -(n-1)^2 -3
={ n^2 -n^2 +2n-1 }
= (2n -1)
so,
Tn =(2n -1)
so, 20th term = T20 =2(20) -1 = 39
Tn = Sn - S(n-1)
Tn =n^2 +3 -(n-1)^2 -3
={ n^2 -n^2 +2n-1 }
= (2n -1)
so,
Tn =(2n -1)
so, 20th term = T20 =2(20) -1 = 39
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