Question

the sum of n terms of (1-1/n)+(2-4/n)+(3-9/n)+... =

Answer 1

Answer:

$\frac{1 - 1}{n} + \frac{2 - 4}{n} + \frac{3 - 9}{n} \\ = > \frac{ - 2 + ( - 6)}{n} \\ = > \frac{ - 8}{n}$

Answer 2

here is the answer

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