Math, asked by shrutimanjrekar, 8 months ago

The sum of n terms of 8 + 88 + 888 + ... is
8
(10(10" - 1) - 9n)
81
8
(10(10"-1) + 9n)
81
4
(10(10" - 1) - 9n)
81
4
(10(10" - 1) +9n)
81

Answers

Answered by MaLiK28804050

0

Answer:

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