the sum of 'n' terms of a.p= ň2+3n. find its 14th term
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n^2+3n
Let n be 1
(1)+3 (1)
1+3=4
let n be 2
(2)^2+3 (2)
4+6=10
AP= 4,10.........
a=4
d=10-4=6
an=a+(n-1)d
a14= 4+(14-1)6
a14= 4+(13)6
a14= 4+78
a14= 82
Let n be 1
(1)+3 (1)
1+3=4
let n be 2
(2)^2+3 (2)
4+6=10
AP= 4,10.........
a=4
d=10-4=6
an=a+(n-1)d
a14= 4+(14-1)6
a14= 4+(13)6
a14= 4+78
a14= 82
jha12:
यहाँ sum of n term दिया है ना कि nth term
yes
wrong ans
then what's the right ans
I have posted one more question can you answer it please
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this is your perfect answer
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