Question

The sum of n terms of A.P. is 3n^2


+ 6n, then nth term of A.P. is

(a) 6n + 5 (b) 3n – 4 (c) 6n + 3 (d) 1​

Answer 1

Answer:

C

Step-by-step explanation:

Sum of first two terms = S2 = 3(2)2 + 6(2) = 24. ∴ Second term = S2 − S1 = 24 − 9 = 15. Thus, nth term of this A.P. is 3 + 6n.