The sum of n terms of a sequence is 3n2+4n.find 50 term and nth term
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HELLO DEAR,
Given sₙ = 3n2 + 4n
S₁ = 3×1 + 4×1 = 7.
S₂ = 3×4 + 4×2 = 12 + 8 = 20.
First term a₁ = 7 & Second term a₂ = 20 - 7 = 13
and d = 13 - 7 = 6.
Now ₅₀th term an = 7 + ( 50 - 1) 6
a₅₀ = 7 + 49 x 6
a₅₀ = 7+294 =301
I HOPE ITS HELP YOU DEAR,
THANKS
Given sₙ = 3n2 + 4n
S₁ = 3×1 + 4×1 = 7.
S₂ = 3×4 + 4×2 = 12 + 8 = 20.
First term a₁ = 7 & Second term a₂ = 20 - 7 = 13
and d = 13 - 7 = 6.
Now ₅₀th term an = 7 + ( 50 - 1) 6
a₅₀ = 7 + 49 x 6
a₅₀ = 7+294 =301
I HOPE ITS HELP YOU DEAR,
THANKS
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