The sum of n terms of a series is (n^2+2n) for all values of n. Find the first 3 terms of the series.
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Answered by
23
Sn=n*2+2n
S1=1*2+2(1)
=1+2
=3=a1
S2=2*2+2(2)
=4+4
=8
S2-S1=a2
8-3=5
a2=5
d=a2-a1
=5-3
=2
a1=3
a2=5
a3=3+2(2)=7
S1=1*2+2(1)
=1+2
=3=a1
S2=2*2+2(2)
=4+4
=8
S2-S1=a2
8-3=5
a2=5
d=a2-a1
=5-3
=2
a1=3
a2=5
a3=3+2(2)=7
Answered by
4
Answer:
same as above
I hope this will help you to understand
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