The sum of n terms of an A.P.is 3n'2+5n/2& common difference is 3.What is first term?
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this is the answer with step by step explanation
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Step-by-step explanation:
S = 3n'2+5n/2 & common difference is 3.
S = 3n²+5n/2 = n/2 ( 5 +6n) = n/2 ( 5 +6n -6 +6 ) = n/2 { 11 +6(n -1 )}
= n/2{2a+(n-1)d}
comparing
a = 11/2
an other solution
s(n) = 3n²+5n/2
s(1) = 3+5/2 = 11/2
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