The sum of n terms of an A.P. is 3N^2, the term which equal 159 is
13
21
27
NONE OF THESE
Answers
Answered by
1
27 ɪs ᴛʜᴇ ʀɪɢʜᴛ ᴀɴsᴡᴇʀ
ʜᴏᴘᴇ ɪᴛ ɪs ʜᴇʟᴘғᴜʟ ғᴏʀ ʏᴏᴜ!!
Answered by
83
Tn=Sn-(Sn-1)
Tn=159
Sn=3n^2+5
Sn-1=3(n-1)^2+5
Sn-1=3(n^2–2n+1)+5
Sn-1=3n^2–6n+3+5
Sn-1=3n^2–6n+8
Substituting the values in the first eqn
159=3n^2+5-(3n^2–6n+8)
159=3n^2+5–3n^2+6n-8
159=6n-3
159+3=6n
6n=162
N=27
Your answer is 27th value
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