The sum of n terms of an A.P. is 3n2+ 5. Which term of the A.P. equals 159?
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Answer:
152 term
Step-by-step explanation:
Sn=3n²+5
S1= 3(1)²+5
S1= 8
S1=a1= 8
S2= 3(2)²+5
S2= 17
a2=S2-S1
a2= 17-8
a2=9
a2-a1=d
9-8=d
1=d
a+(n-1)d=159
8+(n-1)1=159
n+7=159
n=159-7
n=152
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