Question

The sum of n terms of an A.P whose first term is 5
and common difference is 36 is equal to the sum of
2n terms of another A.P. whose first term is 36 and
common difference is 5. Find n.​

Answer 1

Answer:

sum of n terms of 1st = (n/2)(10 + 36(n-1))

= (n/2)(36n - 26)

sum of 2n terms of 2nd = (2n/2)(72 + 5(2n-1))

= n(10n + 67)

(n/2)(36n - 26) = n(10n + 67)

divide by n, and multiply by 2

36n - 26 = 20n + 134

16n = 160

n = 10

check:

sum(10 for 1st) = 5(10 + 36(9)) = 1670

sum(20 for 2nd) = 10(72 + 19(5)) = 1670

Step-by-step explanation:

hope you understand

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