the sum of n terms of an A.P with series Sn=2n^2 + 6n. Find first term of common difference
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Answer:
common difference = 24
first term = 12.
Step-by-step explanation:
S n=2 n^2 + 6 n
as we know that s 2 - s 1 = a 1
s 2 = 2( 2)^2 + 6 (2)
= 8 + 12 = 20
s 1 = 2 1 ^2 + 6 (1) = 2 + 6 = 8
s 3 = 2 n^2 + 6 n
a 1 is the first term = 20 - 8 = 12.
a 2 = s 2 - s 3 = 2 (3)^2 + 6 (3)
= 18 + 18 = 36
common difference = a 2 - a 1 = 36 - 12 = 24
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