the sum of n terms of an AP is 2n+3n^2.Find the nth term of AP
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Sn=2n+3n^2
S1=2.1 + 3(1)^2
S=2+3=5
S2=2.2 + 3(2)^2
S2=4+12=16
S2-S1=a1
a1=16-5=11
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S1=2.1 + 3(1)^2
S=2+3=5
S2=2.2 + 3(2)^2
S2=4+12=16
S2-S1=a1
a1=16-5=11
hope it helped you!!!
mark it brainliest if u liked it.!!!
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