The sum of n terms of an ap is 2n+3n2 determine ap find the 10 term
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Sn = 3n²+2n
S1 = a1 = 3+2 = 5
Now a2= S2-S1 thus
a2 = 16-5 = 11
Now a2-a1 = common difference = d
So d = 6
Now
An = a+(n-1)d
An = 5+(n-1)6
ATQ
A10 = 5+(9)6 = 5+54 => 59
So tenth term is 59.
S1 = a1 = 3+2 = 5
Now a2= S2-S1 thus
a2 = 16-5 = 11
Now a2-a1 = common difference = d
So d = 6
Now
An = a+(n-1)d
An = 5+(n-1)6
ATQ
A10 = 5+(9)6 = 5+54 => 59
So tenth term is 59.
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