The sum of n terms of an ap is 3n square +2n.Find the series and the 10th term
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Sn = 3n²+2n
Let n be 1
S1 = 3(1²)+2(1) = 3+2 = 5
a1 = 5
Let n be 2
S2 = 3(2²)+2(2) = 12+4 =16
S2 = a1+a2 = 16
5+a2 = 16
a2 = 11
d = a2-a1 = 11-5 = 6
d = 6
AP:5,11,...
a10 = a +9d = 5+54 = 59
a10 = 59
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