The sum of n terms of an AP is 3n2 + 4n . Find the AP
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please mark as brainelest answer please it's a humble request
Step-by-step explanation:
T
n
=S
n
−S
n−1
.(1)
Now S
n
=3n
2
+4n
∴S
n−1
=3(n−1)
2
+4(n−1)=3n
2
−2n−1
∴T
n
=(3n
2
−4n)−(3n
2
−2n−1), by (1)
=6n+1
∴T
1
=7,T
2
=13,T
3
=19,______
∴a=7,d=6.
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