The sum of n terms of an AP is 3n² + 5n. Find the AP. Hence find its 15th term.
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Sn = 3n^2 + 5n
Sn – 1 = 3(n – 1)^2 + 5(n – 1)
= 3(n^2 + 1 – 2n) + 5n – 5
= 3n^2 + 3 – 6n + 5n – 5
= 3n^2 – n – 2
an = Sn – Sn – 1 = 3n^2 + 5n – (3n^2 – n – 2)
= 6n + 2
AP is 8, 14, 20, ....................
a(15) => a + 14d = 8 + 14(6) = 92
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