The sum of n terms of an ap is 5n^2-3n find the ap and also its 10th term
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Sn = 5 n^2 - 3n
we know that
Tn = Sn - Sn-1
so
Tn = 5n^2 -3n - 5 (n-1)^2 +3(n-1)
= 10n - 5
now
T10 = 10×10-5
=95
we know that
Tn = Sn - Sn-1
so
Tn = 5n^2 -3n - 5 (n-1)^2 +3(n-1)
= 10n - 5
now
T10 = 10×10-5
=95
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