the sum of n terms of an AP is 5n square - 3n. find the AP hence find its 10nth term
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Answered by
3
Putting n=1, 5n²-3n
=5-3=2
Putting n=2, 5n²-3n
=14
Therefore 2nd term is 14-2=12
Therefore AP is 2, 12, 22 ... and so on.
10th term=a+9d
=2+9*10
=2+90
=92
=5-3=2
Putting n=2, 5n²-3n
=14
Therefore 2nd term is 14-2=12
Therefore AP is 2, 12, 22 ... and so on.
10th term=a+9d
=2+9*10
=2+90
=92
Answered by
0
sn=5n square -3n
differentiation n=10
tn=10n+(-3-5)
10×10-8=92
differentiation n=10
tn=10n+(-3-5)
10×10-8=92
Mil463yahoocom:
can u explain it properly
answer edit nahi kar sakta ab
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