Question

The sum of n terms of an AP is (5n2 – 3n). Find the AP and hence find its 10th term.​

Answer 1

Answer:

AP is 2,14,26, 38..

A10 = 470

Step-by-step explanation:

An= 5n² - 3n

A1= 5-3 = 2

A2= 5×(2)² - (3×2)= 14

d= A2-A1= 14-2 = 12

so, AP is 2,14,26,38 and so on.

And 10th term of this AP is,

A10 = 5×(10)² - (3×10) = 500 - 30 = 470

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