Math, asked by 0610aadq, 3 months ago

the sum of n terms of an AP is n² - n, then It's first term is?​

Answers

Answered by bhavanirapolu85
0

Answer:

this is the answer

Step-by-step explanation:

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Answered by mathdude500
2

Answer:

The sum of first n terms of an AP is (n² - n) then first term of AP is 0.

Step-by-step explanation:

Given that, sum of first n terms of an AP is n² - n.

So,

\sf \: S_n =  {n}^{2} - n \\  \\

On substituting n = 1, we get

\sf \: S_1 =  {1}^{2} - 1 \\  \\

\sf \: S_1 =  1 - 1 \\  \\

\sf \: S_1 =  0 \\  \\

\implies\sf \: \sf \:T_1 =  S_1 =  0 \\  \\

Hence, The sum of first n terms of an AP is (n² - n) then first term of AP is 0.

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Additional Information

↝ nᵗʰ term of an arithmetic progression is,

\begin{gathered}\bigstar\:\:{\underline{{\boxed{\sf{{a_n\:=\:a\:+\:(n\:-\:1)\:d}}}}}} \\ \end{gathered}

↝ Sum of n  terms of an arithmetic progression is,

\begin{gathered}\bigstar\:\:{\underline{{\boxed{\sf{{S_n\:=\dfrac{n}{2} \bigg(2 \:a\:+\:(n\:-\:1)\:d \bigg)}}}}}} \\ \end{gathered}

Wʜᴇʀᴇ,

a is the first term of the progression.

n is the no. of terms.

d is the common difference.

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