Question

The sum of n terms of an AP is nsquare -3n . Find the seventeenth term of the AP

Answer 1

Step-by-step explanation:

Here Sn=3n+n2

Now, first term a=S1⇒a=3×1+12=4 and

Sum of first two terms=a1+a2=a+(a+d)=S2=3×2+22=10

⇒2a+d=10⇒8+d=10⇒d=2

Now, a2=a+d⇒a2=4+2=6

a3=a+2d⇒a3=4+2×2=8

a15=a+14d⇒a15=4+14×2=32

Hope this will help you.

Answer 2

Answer:

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Thank uh...!!