The sum of n terms of ap is 3n^2+4n.find ap of these nos
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SUM OF AP = 3n^2 +4n
S₁ = 3(1)^2+ 4(1)
S₁ = 3+4 =7
S₁= a₁ = 7
S₂ = 3(2)^2+4(2)
S₂ = 12 +8
S₂ = 20
a₂ = S₂-S₁ = 20-7=13
S₃ = 3(3)^2+4(3)
S₃ = 27+12
S₃ = 39
a₃ = S₃-S₂ = 39-20 = 19
So AP. - 7,13,19....
a= 7 d=6
S₁ = 3(1)^2+ 4(1)
S₁ = 3+4 =7
S₁= a₁ = 7
S₂ = 3(2)^2+4(2)
S₂ = 12 +8
S₂ = 20
a₂ = S₂-S₁ = 20-7=13
S₃ = 3(3)^2+4(3)
S₃ = 27+12
S₃ = 39
a₃ = S₃-S₂ = 39-20 = 19
So AP. - 7,13,19....
a= 7 d=6
haritha511:
Thank u sooooo much
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