the sum of n terms of ap is
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Let a be the first term of the A.P and d be the common difference such that the A.P is
a,a+d,a+2d,a+3d,....,a+(n-1)d.
where n be the number of terms.
Sum of n terms of A.P=n/2[2a+(n-1)d]=n/2[a+l]
where l is the last term , l=a+(n-1)d
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