The sum of n terms of the AP 17,25,33,41,....is 627. Find the no of terms of Ap
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sn=n/2(2a+(n-1)d)
627=n/2(2×17+(n-1)8)
627=n/2(34+8n-8)
1254=n(26+8n)
1254=26n+8n^2
8n^2+26n-1254=0
then factorise it and you will get answer.Thank u
627=n/2(2×17+(n-1)8)
627=n/2(34+8n-8)
1254=n(26+8n)
1254=26n+8n^2
8n^2+26n-1254=0
then factorise it and you will get answer.Thank u
ramyareddy0697:
Plz do factorize I'm unable get the answer the answer should be 11
Answered by
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Step-by-step explanation:
n = 11 it is a write answer
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