The sum of n terms of the series 0.3+0.03+0.003+.........
Answers
Answered by
0
Answer:
0.0003
Step-by-step explanation:
0.3/10+0.003/100+0.003/1000+0.0003/10000
Answered by
1
Answer:
answer is:
Step-by-step explanation:
a=0.3
d=0.03-0.3
=-0.27
s n=n/2(2a+(n-1)d)
=n/2(0.6+(n-1)-0.27)
=n/2(0.6-0.27n+0.27)
=n/2(0.33-0.27n)
=0.33n-0.27n^2/2
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