Question

The sum of n terms of two arithmetic progression
are in the ratio (3n+8): (7 + 15). Find the ratio of
their 12th terms.
(a) 7:16 (b) 5:16 (c) 3:16 (d) 1:16
10
TL​

Answer 1

Step-by-step explanation:

(3n+8):(7+15)

=(11n):(22)

=11n+22

=33

=3n:3

Answer 2

Answer:

716

Step-by-step explanation:

The sum of n terms of two arithmetic progressions are in the ratio (3n+8):(7n+15)dot Find the ratio of their 12th terms. Let a is the first term and d1 is the common difference of the first AP. Let b is the first term and d2 is the common difference of the second AP. So, required ratio is 716.