The sum of n terms of two arithmetic progressions are in ratio (3n+8):(7n+15). Find the ratio of their (i)12th terms (ii)15th terms.
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Answer:1324 - 895794=7586';/[6758=697-]
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2. In an AP of 50 terms, the sum offirst 10 terms is 210 and the sum of its last 15 ... If there are 1 to 12 classes in the school and each class has two sections, find ... n terms of two A.Psis (7n + 1): (4n+27), then find the ratio of their 9th terms. ... In an A.P. if 3 times its 3rd term is equal to 7 times its 7th term then find the 10th term.
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