Question

The sum of n terms of two arithmetic progressions are in the ratio 3n + 5 : 4n + 7 . Find the ratio of their 26th terms

Answer 1

Answer:

107:127

Step-by-step explanation:

S¹=3(1)+5:4(1)+7

=8:11

S¹=a¹=8:11

S²=3(2)+5:4(2)+7

=11:15

a²=S²-a¹

a²=11-8:15-11

a²=3:4

d=a²-a¹

d=3-8:4-11

d= -5: -6

a²⁴=a+(n-1)d:a+(n-1)d

a²⁴=8+(23)(-5):11+(23)(-6)

a²⁴=8-115:11-138

a²⁴= -107: -127

Ratio is 107:127

HOPE THIS IS HELPFUL TO YOU

PLEASE MARK AS BRAIN LIST ANSWER