Math, asked by IISailorSkyII, 1 day ago

The sum of n terms of two arithmetic progressions are in the ratio 5n + 4 : 9n + 6. Find the ratio of their 18th term.​

Answers

Answered by Anonymous
1

Step-by-step explanation:

There are two AP with different first term and common difference

For the first AP

Let first term be = a

Common difference = d

Sum of n terms = S,=[2a+ (n-1)d]

&n term = an = a + (n-1)d

For the second AP

Let first term be = A

common difference = DD

Sum of n terms S12A + (n-1)D]

& nth term = A = A+ (n-1)D

Answered by rameshrajput16h
1

Answer:

your answer will in this photo

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