The sum of n terms of two arithmetic progressions are in the ratio 5n + 4 : 9n + 6. Find the ratio of their 18th term.
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Step-by-step explanation:
There are two AP with different first term and common difference
For the first AP
Let first term be = a
Common difference = d
Sum of n terms = S,=[2a+ (n-1)d]
&n term = an = a + (n-1)d
For the second AP
Let first term be = A
common difference = DD
Sum of n terms S12A + (n-1)D]
& nth term = A = A+ (n-1)D
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