The sum of natural number is 20while their difference is 4 find number
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Answer:
let x and y be the 2 natural no.
x + y = 20 and x - y = 4
solving u will get x = 8 and y = 12
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Answered by
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Let the required natural numbers are a and b, where a is the larger number than b.
It is given in question that the sum of numbers is 20 and difference between them is 4 .
According to the question :
Sum of both the numbers = 20
Sum of a and b = 20
= > a + b = 20 ---: ( 1 )
Also, their difference is 4 .
Difference between a and b = 4
= > a - b = 4 ----: ( 2 )
Now, adding ( 1 ) and ( 2 ),
= > a + b + ( a - b ) = 20 + 4
= > a + a + b - b = 24
= > 2a = 24
= > a = 12
Then, substituting the value of a in ( 1 ),
= > a + b = 20
= > 12 + b = 20
= > b = 20 - 12
= > b = 8
Hence,
Required natural numbers are 12 and 8.
It is given in question that the sum of numbers is 20 and difference between them is 4 .
According to the question :
Sum of both the numbers = 20
Sum of a and b = 20
= > a + b = 20 ---: ( 1 )
Also, their difference is 4 .
Difference between a and b = 4
= > a - b = 4 ----: ( 2 )
Now, adding ( 1 ) and ( 2 ),
= > a + b + ( a - b ) = 20 + 4
= > a + a + b - b = 24
= > 2a = 24
= > a = 12
Then, substituting the value of a in ( 1 ),
= > a + b = 20
= > 12 + b = 20
= > b = 20 - 12
= > b = 8
Hence,
Required natural numbers are 12 and 8.
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