Math, asked by ravi8939, 1 year ago

the sum of natural number upto 200 excluding those divisible by 5 is​

Answers

Answered by Anonymous
5

Answer:

Step-by-step explanation:

1,2,3,4 ......200 you can calculate the sum of this  

200/2 * (1+200) = 20100  

The next series is  

5,10,15 .... 200 (all the numbers divisible by 5) the sum of this is  

40/2 * (200+5) = 4100  

So the required total = 20100-4100 = 16000

Answered by raj981
4

Step-by-step explanation:

(1+2+3+4+5....+199+200)-(5+10+15....+195+200)

 =  \frac{200(200 + 1)}{2}  - 5(1 + 2.... + 40) \\  = 100 \times 201 - 5( \frac{40(40 + 1)}{2} ) \\ =  20100 - 5 \times 20 \times 41 \\ =  20100 - 4100 \\ =  16000

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