The sum of natural number which is less than 100 which are divisible by 7
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the sequence of the number divisible by 7 is 7,14,21.........,98 which form an AP of first term 7 ,last term=98and CD =4
let 98 be 'n" term of the AP
then, A n=98
A+(n-1)d=98
7+(n-1)7=98
n-1=13
n=14
now, S 14=(14÷2)(7+98)
=735
HOPE IT HELP YOU
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Answer:the sequence of the number divisible by 7 is 7,14,21.........,98 which form an AP of first term 7 ,last term=98and CD =4
let 98 be 'n" term of the AP
then, A n=98
A+(n-1)d=98
7+(n-1)7=98
n-1=13
n=14
now, S 14=(14÷2)(7+98)
=735
HOPE IT HELP YOU
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