the sum of number and its reciprocal is 10/8 find the number
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Answer:
no solution
Step-by-step explanation:
Let the numer be x
Thus it's reciprocal = 1/x
Now x +1/x = 10/8
x^2 + 1 = 10x/8
8x^2 + 8 = 10x
4x^2 + 4 = 5x
4x^2 - 5x + 4 = 0
D = b^2 - 4ac
Here b = - 5 and a = 4 and c = 4
D = 25 - 64 = Negative
Thus no positive solution is possible
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