the sum of number and its reciprocal is 17 /4 find the number
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Hey friend..!! here's your answer
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Let the number = x
and its reciprocal = 1 / x
According to question,
x + (1/x) = 17 / 4
(x^2 + 1 ) / x 17 / 4
4x^2 + 4 = 17x
4x^2 - 17x + 4 = 0
a = 4 , b = -17 , c = 4
D = b^2 - 4ac
= (-17)^2 - 4(4)(4)
= 289 - 64
= 225
By using quadratic formula,
-b + rootD / 2a or -b - rootD /2a
-(-17) + root 225 /8
17 + 25 /8
4
Or
-(-17) - root 225/8
17 - 15 / 8
1/4
So that the number is 4 and its reciprocal is 1/4
___________________
#Hope its help you dear#
☺
_________________________
Let the number = x
and its reciprocal = 1 / x
According to question,
x + (1/x) = 17 / 4
(x^2 + 1 ) / x 17 / 4
4x^2 + 4 = 17x
4x^2 - 17x + 4 = 0
a = 4 , b = -17 , c = 4
D = b^2 - 4ac
= (-17)^2 - 4(4)(4)
= 289 - 64
= 225
By using quadratic formula,
-b + rootD / 2a or -b - rootD /2a
-(-17) + root 225 /8
17 + 25 /8
4
Or
-(-17) - root 225/8
17 - 15 / 8
1/4
So that the number is 4 and its reciprocal is 1/4
___________________
#Hope its help you dear#
☺
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