Question

The sum of number is 58 the greater exceeds twice the smaller number by 1 find the number

Answer 1

let the smaller number be x
then the greater number will be 2x+1
so; 2x+1+x=58
3x+1=58
3x=58-1
3x=57
x=57/3
×=19
so the smaller number is 19
greater number is 19×2+1=39