the sum of number when a number is increased by 10% and decreased by 10% is 100 what is the number
Answers
Answered by
8
Solution :-
Let the required number be 100.
Then, according to the question.
⇒ Firstly, the number is increased by 10 %
⇒ 100 + (100*10)/100
⇒ 100 + 10
= 110
Secondly, it is decreased by 10 %
⇒ 110 - (110*10)/100
⇒ 110 - 11
⇒ 99
Net increase or decrease percentage
= (Original Number - New Number)*100/100
⇒ (100 - 99)*100/100
⇒ (1*100)/100
⇒ 100/100
= 1 %
So, net decrease is 1 %.
Let the required number be 100.
Then, according to the question.
⇒ Firstly, the number is increased by 10 %
⇒ 100 + (100*10)/100
⇒ 100 + 10
= 110
Secondly, it is decreased by 10 %
⇒ 110 - (110*10)/100
⇒ 110 - 11
⇒ 99
Net increase or decrease percentage
= (Original Number - New Number)*100/100
⇒ (100 - 99)*100/100
⇒ (1*100)/100
⇒ 100/100
= 1 %
So, net decrease is 1 %.
Answered by
30
let the number be 'x '
increased number = x + 10% of x
x + 0.1x = 1.1 x
decreased number = x - 10% of x
= x - 0.1x = 0.9x
sum = 100
1.1x + 0.9x = 100
2x = 100 => x = 50
Answer: required number = 50
increased number = x + 10% of x
x + 0.1x = 1.1 x
decreased number = x - 10% of x
= x - 0.1x = 0.9x
sum = 100
1.1x + 0.9x = 100
2x = 100 => x = 50
Answer: required number = 50
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