Question

the sum of numbers 1 to 100,which are divisible by 13​

Answer 1

here's your answer:-

the ap of numbers 1 to 100 divisible by 13 will be:-
13,26,39---------------91
therefore-
a=13,d=13,n=?,l=91
l=a+(n-1)d
91=13+(n-1)13
13(n-1)=91-13
13(n-1)=78
(n-1)=78/13
(n-1)=6
n=6+1
n=7

sum of the number s will be:-
Sn
Sn = n/2(a+l)
Sn = 7/2(13+91)
Sn = 7/2*104
Sn = 7*52
Sn = 364

Answer==364

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