Math, asked by architachaurasia123, 1 year ago

The sum of numbers is 80 and the greater number exceeds twice the smaller by 11 . Find the numbers .

Answers

Answered by ArijitPatra
2
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Answered by 19012004
2

Answer:

Let the smaller number be x

Greater number= 80-x

80-x=2x+11

80-11=2x+x

69=3x

x=69/3

x=23

Smaller number is 23

Greater number is 80-23= 57

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