Question

The sum of numerator and denominator of a fraction is 12. If the denominator is increased by 1, the fraction becomes 7/6 Find the fraction.

Answer 1

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Answer 2

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Let the required fraction be

$\frac{x}{y}$

Then,

$x + y = 12.........eq(1)$

And,

$\frac{x}{y + 3 \: } = \frac{1}{2}$

$2 x = y + 3$

$2x - y = 3.............eq(2)$

On adding 1 and 2, we get,

$(x + y = 12) \\ + ( 2x - y = 3 )$

_______________

$3x + 0 = 15$

$x \: = \: 5$

On putting x=5 in equation 1, we get,

$5 + y = 12$

$y = 7$

Therefore, the required fraction is $\frac{5}{7}$