Question

The sum of numerator and denominator of a fraction is 3 less than twice the denominator if each of
the numerator and derominator is decreased by 1. the fraction becomes1/2 Find the fraction.​

Answer 1

Answer:

the numerator be 'x' and denominator be ' y'

then,

the sum of the numerator and denominator of a fraction is 3 less than the twice is x+y=2y-3 :- x-y+3=0 - equation 1

if the numerator and denominator is decreased by 1 then

x-1/y-1=1/2 :- 2(x-1) = 1(y-1) :- 2x-y-1=0 -equation 2

then equation 1 = equation 2

x-y+3=2x-y-1 :- x=4

from the equation 1 

x-y+3=0 :- 4-y+3=0 :- y=7

there fore the fraction is 3/7 

Step-by-step explanation: I HOPE THIS WILL HELP UHH !

Answer 2

Let the fraction be

$\frac{N}{D}$

From the given conditions,

N+D=2D-3

N=D-3

&

$\frac{n - 1}{d - 1} = \frac{1}{2}$

2N-2=D-1

2(D-3)-2=D-1

2D-6=D-1

2D-D=6-1

D=5

Therefore, N=5-3=2

Therefore, ratio is

$\frac{N}{D} = \frac{2}{5}$