Question

The sum of numerator and denominator of a fraction is 3 less than twice the denominator . If each of the numerator and denominator is decreased by 1 , the fraction becomes 12.Find the Fraction

Answer if you can ???? ​

Answer 1

Answer:-

Let, the numerator be 'x'
Denominator be ' y'
then,
the sum of the numerator and denominator of a fraction is 3 less than the twice is
x+y=2y-3 :- x-y+3=0 -equation 1
if the numerator and denominator is decreased by 1 then
x-1/y-1=1/2 :- 2(x-1) = 1(y-1) :- 2x-y-1=0 -equation 2
then equation 1 = equation 2
x-y+3=2x-y-1 :- x=4
from the equation 1 
x-y+3=0 :- 4-y+3=0 :- y=7
there fore the fraction is 3/7 

Hope this helps you

Answer 2

The numerator be 'x' and denominator be ' y'

then,

the sum of the numerator and denominator of a fraction is 3 less than the twice is x+y=2y-3 :- x-y+3=0 - equation 1

if the numerator and denominator is decreased by 1 then

x-1/y-1=1/2 :- 2(x-1) = 1(y-1) :- 2x-y-1=0 -equation 2

then equation 1 = equation 2

x-y+3=2x-y-1 :- x=4

from the equation 1 

x-y+3=0 :- 4-y+3=0 :- y=7

there fore the fraction is 3/7 

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