Question

The sum of numerator and denominator of a fraction is greater by 1 than thrice the numerator is decreased by 1 then the fraction reduced to 1/3 find the fraction.

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Answer 1

Answer:

Let the fraction =

y

x

First condition :

⇒x+y=2y−3

⇒x−y=−3

Second condition :

⇒

y−1

x−1

=

2

1

⇒2x−2=y−1

⇒2x−y=1

Subtract two equations ;

⇒2x−x=1+3⇒x=4

substitute in above equation

⇒y=1+8⇒y=7

∴ the fraction =

7

4

Explanation:

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