The sum of numerator and denominator of a fraction is greater by 1
than thrice the numerator. If the numerator is decreased by 1 then the
fraction reduces to Find the fraction.
Answers
Seems like the question contains "fraction reduces to 1/3
Answer:
4/9
Step-by-step explanation:
Let the numerator be 'x' and denominator be 'y'. Thus, fraction be x/y.
Sum of x and y = 1 + 3x
x + y = 1 + 3x
y = 1 + 2x
If the numerator is decreased by 1, fraction becomes 1/3.
⇒ (x - 1)/y = 1/3
⇒ (x - 1)/(1 + 2x) = 1/3
⇒ 3(x - 1) = 1 + 2x
⇒ 3x - 3 = 1 + 2x
⇒ 3x - 2x = 4 ⇒ x = 4
thus, y = 1 + 2x = 1 + 2(4) = 9
∴ Fraction = x/y = 4/9
Given :-
Sum of numerator and denominator of a fraction is greater by 1
than thrice the numerator. If the numerator is decreased by 1 then the
fraction reduces to 1/3
To Find :-
Fraction
Solution :-
Let the fraction be x/y
Now
When decreased by 1
By cross multiplication
(y) = 3(x - 1)
y = 3x - 3
y = 3x - 3
Substituting the value of y
Finding the numerator