Question

The sum of numerator and denominator of a fraction is 4 more than twice the numerator if the numerator and denominator are increased by 3 they are in ratio 2:3 find the fraction using elimination method

Answer 1

let numerator be X and denominator be Y
X+Y= 4+2X. (1)
X+3/Y+3 = 2/3. (2)
multiply equation (2) by 3
the equation is all there find out using the method of elimination ( multiply any equation by - and eliminate either X or Y get the value of one and put it in any equation u will get the answer

Answer 2

Answer:

Step-by-step explanation:

Given :-

The sum of numerator and denominator of a fraction is 4 more than twice the numerator if the numerator.

Denominator are increased by 3 they are in ratio 2:3.

To Find :-

The Fraction

Solution :-

Let the required fraction be x/y .  

According to the question

1st Equation

x + y = 4 + 2x  

⇒ y – x = 4 ……(i)  

2nd Equation

After changing the numerator and denominator  

New numerator = x + 3  

New denominator = y + 3  

⇒ x+3/ y+3 = 2/3  

⇒ 3(x + 3) = 2(y + 3)  

⇒ 3x + 9 = 2y + 6  

⇒ 3x + 2y = 3 ……(ii)  

Multiplying (i) by 3

⇒ 3y – 3x = 12

Subtracting Eq (i) and (ii)

⇒ y = 9

Putting y value in Eq (i)

⇒ y – x = 4

⇒ 9 – x = 4

⇒ x = 9 – 4

⇒ x = 5  

Hence, the required fraction is 5/9 .